SOLUTIONS 001
Solution 001
CHM 101 CHEMISTRY
1.c (alpha particles have the lowest penetrating power)
2.b (fission is splitting apart)
3.b (P orbital has 6 electrons maximum. The configuration is deficient of 2 electrons)
4.d (0K is absolute zero)
5.c (Entropy is a measure of the randomness of a system. Positive entropy favours spontaneity)
6.d
7.b
8.b (K2MnO4 => 2+Mn-8 =0; Mn=8-2=6.)
9.a (for endothermic reactions, ∆H +ve; for exothermic reactions ∆H -ve)
10.b decrease or increase in concentration of reactant or product affects equilibrium position, shifting it to the right or left. Decrease in concentration of X, favours production of X.)
11.c (MgO => Mg-2=0; Mg=2)
12.d
13.d (Ar = 18.)
14.c ( [H+] =10^ - pH)
15.a (pH = -log [H+] )
16.b (Ph = 14 - pOH)
17.c (1 mol H20 = 18g. => 18g=6.02×10^23 mol. => 2g = X. => X= {2×6.02×19^23} / 18}
18.d (one way reactions proceed in one direction only)
19.d ( CaVa=CbVb )
20.c K2Cr2O7 => 2+Cr2-14=0 ; Cr2=14-2=12 ; Cr =+6.)
2.b (fission is splitting apart)
3.b (P orbital has 6 electrons maximum. The configuration is deficient of 2 electrons)
4.d (0K is absolute zero)
5.c (Entropy is a measure of the randomness of a system. Positive entropy favours spontaneity)
6.d
7.b
8.b (K2MnO4 => 2+Mn-8 =0; Mn=8-2=6.)
9.a (for endothermic reactions, ∆H +ve; for exothermic reactions ∆H -ve)
10.b decrease or increase in concentration of reactant or product affects equilibrium position, shifting it to the right or left. Decrease in concentration of X, favours production of X.)
11.c (MgO => Mg-2=0; Mg=2)
12.d
13.d (Ar = 18.)
14.c ( [H+] =10^ - pH)
15.a (pH = -log [H+] )
16.b (Ph = 14 - pOH)
17.c (1 mol H20 = 18g. => 18g=6.02×10^23 mol. => 2g = X. => X= {2×6.02×19^23} / 18}
18.d (one way reactions proceed in one direction only)
19.d ( CaVa=CbVb )
20.c K2Cr2O7 => 2+Cr2-14=0 ; Cr2=14-2=12 ; Cr =+6.)
SOLUTIONS 001
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Sunday, August 21, 2016
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